a624. 4. Password Analyzer -- HP CodeWars2007 | From: [111.254.212.6] | 發表日期 : 2014-10-06 22:01

#include<cstdio>

#include<cstring>

int main(){

  char x[1000];

  while(~scanf("%s",&x)){

   int s=strlen(x),sum=0,fact1=0,fact2=0,fact3=0;

  if(s>=8) sum++;

  for(int i=0;i<s;i++) 

   {if((x[i]>='a'&&x[i]<='z')) fact1++;

   else if(x[i]>='A'&&x[i]<='Z') fact2++;

   else fact3++;

  }

   if(fact1>0&&fact2>0) sum++;

  if(fact1+fact2>0&&fact3>0) sum++;

  

  printf("This password is ");

  if(sum==3) printf("STRONG");

  else if(sum==2) printf("GOOD");

  else if(sum==1) printf("ACCEPTABLE"); 

  else printf("WEAK");

  printf("\n");

}}