#11350: C++清晰正解


TzuchunChen (陳子濬)


#include <iostream>

/* run this program using the console pauser or add your own getch, system("pause") or input loop */
using namespace std;
int main(int argc, char** argv) {
 
 int M, D, S;
 
 while (cin >> M >> D )
 {
 S=(M*2+D)%3 ;
 
 if(S==0)
 {cout << "普通" << endl;}
 
 else if(S==1)
 {cout << "吉" << endl;}
 
 else if(S==2)
 {cout << "大吉" << endl;}
 
 }
 return 0;
}