#12494: 解題心得


56565656 (傑尼龜好可愛)


-38 到36用迴圈跑過一次,如果f(x) * f(x+1) < 0 就印出來

printf("N0THING! >\\\\\\<\n");

cout<<"Too many... = =\"\n"; 

這兩個輸出很挖坑呵