我的程式如下
#include <stdio.h>
#include <stdlib.h>
int main()
{
unsigned short n, i;
unsigned threeK[3] = {0,0,0};
unsigned num;
scanf("%d", &n);
for( i=0 ; i<n ; i++ )
{
scanf("%d", &num);
switch(num%3)
{
case 0:
threeK[0]++;
break;
case 1:
threeK[1]++;
break;
case 2:
threeK[2]++;
break;
}
}
printf("%d %d %d", threeK[0], threeK[1], threeK[2]);
return 0;
}
我如果把 num 的宣告用 unsigned short 就會有問題,不知道為什麼,請問有人可以幫我解答嗎? 謝謝。
我的程式如下
#include
#include
int main()
{
unsigned short n, i;
unsigned threeK[3] = {0,0,0};
unsigned num;
scanf("%d", &n);
for( i=0 ; i
{
scanf("%d", &num);
switch(num%3)
{
case 0:
threeK[0]++;
break;
case 1:
threeK[1]++;
break;
case 2:
threeK[2]++;
break;
}
}
printf("%d %d %d", threeK[0], threeK[1], threeK[2]);
return 0;
}
我如果把 num 的宣告用 unsigned short 就會有問題,不知道為什麼,請問有人可以幫我解答嗎? 謝謝。
建議是怎樣的型別,在printf
和scanf
裡就要有對等的%
,如:
%d : int
%u : unsigned int
%hd: short int
%hu: unsigned short int