#include<iostream>
#include<math.h>
using namespace std;
unsigned int innum,in,out;
int main(){
cin>>innum;
for(unsigned short lcv = 0;lcv<innum;lcv++){
 cin>>in;
 out = in%10;
 in = (in-(in%10))/10;
 while(in != 0){
  out *= in%10;
  in = (in-(in%10))/10;
 }
 cout<<out<<'\n';
}
return 0;
}

這裡有更短的,我寫的(AC,320KB)