#21164: 遞迴解


peterchang921119@gmail.com (Pizza_Man)


善用遞迴特性,將能寫出非常簡潔優美的程式碼

/*#include<iostream>

 

using namespace std;

 

int gcd(int a,int b){

if(!b)

return a;

 

gcd(b,a%b);

}

 

int main(){

int a,b;

 

while(cin>>a>>b)

cout<<gcd(a,b)<<"\n";

 

return 0;

}*/