#23904: 答案(直接複製即可)


31415 (32陳俞安808)


#include <iostream>

using namespace std;

int main()

{

    short in[10] ;

    for (short i=0 ;i<10;i++ )

    cin >>in[i] ;

    int pt0 ;

    cin >>pt0 ;

    pt0+=30 ;

    short out =0 ;

    for (short i=0 ;i<10;i++ )

if (in[i] <=pt0 ){

    out++ ;}

    cout <<out <<endl ;

}