從題目範例得知1906年為丙午年，直接往前推到1800年

-106分別除10與12再取餘數，把陣列倒著數，可以得知1800年為庚申年。

直接在宣告陣列時把順序排好，輸入n之後直接減1800再取餘數即可拗！

下面有雷，不會再看

----------------------------------------------------------------------------

#include<iostream>

using namespace std;

int main(){

int n;

        string array[] = {"庚","辛","壬","癸","甲","乙","丙","丁","戊","己"};

        string array2[] = {"申","酉","戌","亥","子","丑","寅","卯","辰","巳","午","未"};

while(cin>>n){

n-=1800;

cout<<array[n%10]<<array2[n%12]<<endl;

}

}