如題，以下為程式碼

#include<iostream>
using namespace std;

int main()
{
    string a;
    int n,k=0,l=0;
    char c;
    while(getline(cin,a)) {
        n = a.length();
        for(int i=1; i<n; i++) {
            if (a[i] == a[i-1]) {
                k++;
            }
            if (a[i] != a[i-1]) {
                if(k > l) {
                    c = a[i-1];
                    l=k;
                    k=0;
                }
                else {
                    k=0;
                }
            }
        }
        cout << c << ' ' << l+1 <<'\n';
    }
    cout << endl;
    return 0;
}

可來信索取測資