#26417: Python兩行代碼
Swarfte
(Swarfte Chau)
# J = [eval(x) for x in input().split()]
# print((lambda M,D : "普通" if ((M*2+D)%3 == 0) else ("吉" if ((M*2+D)%3 == 1) else "大吉"))(J[0],J[1]))
#26418: Re:Python兩行代碼
406490150@gms.tku.edu.tw
(我是朱朱)
# J = [eval(x) for x in input().split()]# print((lambda M,D : "普通" if ((M*2+D)%3 == 0) else ("吉" if ((M*2+D)%3 == 1) else "大吉"))(J[0],J[1]))
第一行可以用M,D = map(int, input().split())即可，會自動拆解
第二行不需要if else，改用index索引即可(普通,吉,大吉)[算出的答案來索引]
#26598: Re:Python兩行代碼
tonysu1204@gmail.com
(東毅中)
# J = [eval(x) for x in input().split()]# print((lambda M,D : "普通" if ((M*2+D)%3 == 0) else ("吉" if ((M*2+D)%3 == 1) else "大吉"))(J[0],J[1]))
照你這種寫法，我c++都能兩行解
#include<stdio.h>
int main(){int a,b; int *n[] ={"普通","吉","大吉"};scanf("%d%d",&a,&b);printf("%s\n", n[(a*2+b)%3]);return 0;}
#27395: Re:Python兩行代碼
bfkami.d@gmail.com
(kami BF)
# J = [eval(x) for x in input().split()]# print((lambda M,D : "普通" if ((M*2+D)%3 == 0) else ("吉" if ((M*2+D)%3 == 1) else "大吉"))(J[0],J[1]))
照你這種寫法，我c++都能兩行解#include
int main(){int a,b; int *n[] ={"普通","吉","大吉"};scanf("%d%d",&a,&b);printf("%s\n", n[(a*2+b)%3]);return 0;}
你真的懂python?
不懂不要來嘴好嗎...
#28083: Re:Python兩行代碼
jeter.nice@gmail.com
(唯一)
# J = [eval(x) for x in input().split()]# print((lambda M,D : "普通" if ((M*2+D)%3 == 0) else ("吉" if ((M*2+D)%3 == 1) else "大吉"))(J[0],J[1]))
照你這種寫法，我c++都能兩行解#include
int main(){int a,b; int *n[] ={"普通","吉","大吉"};scanf("%d%d",&a,&b);printf("%s\n", n[(a*2+b)%3]);return 0;}
你真的懂python?
不懂不要來嘴好嗎...
笑死看來有C++白癡