#29021: python 壓縮流


hibana2077@gmail.com (tom.li)


#29022: Re:python 壓縮流


hibana2077@gmail.com (tom.li)




#29023: Re:python 壓縮流


hibana2077@gmail.com (tom.li)





https://gist.github.com/hibana2077/2944a009f3a617a89bdf512d452b5b6f

#29031: Re:python 壓縮流


406490150@gms.tku.edu.tw (我是朱朱)





https://gist.github.com/hibana2077/2944a009f3a617a89bdf512d452b5b6f



我是這樣寫的,我覺得這樣可能比你的還難讀ww

from sys import stdin
from collections import Counter
print(sep='\n', *(f'{k} {v}' for k, v in sorted(Counter(stdin.read().upper()).items(), key=lambda x:(x[1],x[0])) if k.isupper()))