#32459: python解法參考
a040. 阿姆斯壯數
| From: [122.116.178.82] |
發表日期
:
2022-10-12 22:54
import math
number = input()
divi_number = number.split(' ')
count = 0
for i in range(int(divi_number[0]), int(divi_number[1])):
times = int(math.log10(i)) + 1
total = 0
str_i = str(i)
for j in range(times):
total += int(str_i[j])**times
if i == total:
print(i, end=" ")
count += 1
if count == 0:
print("none")
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