#35881: 閏年萬用理解方式!!


henry.curry1008@gmail.com (Henry Huang)


n = int(input())
if ((n%100 != 0 and n%4 == 0) or (n%400 ==0)):
    print('a leap year')
else:
    print('a normal year')

#35883: Re: 閏年萬用理解方式!!


900131shawn@gmail.com (nocmos_0623)


閏年萬用最有效率方式!!

if ((year & 3) == 0 && ((year % 25) != 0 || (year & 15) == 0)) {
/* leap year */
}