#38560: 大概就這樣


samlin961112@gmail.com (林哲甫)


#include <bits/stdc++.h>
using namespace std;

int main() {
  int n;
  while(cin>>n){
    int b=pow(n*2,0.5);
    if((b*(b+1))/2<n){b++;}
    if(b%2==0){
      cout<<"TERM "<<n<<" IS "<<b-(b*(b+1))/2+n<<'/'<<1+(b*(b+1))/2-n<<'\n';
    }else{
      cout<<"TERM "<<n<<" IS "<<1+(b*(b+1))/2-n<<'/'<<b-(b*(b+1))/2+n<<'\n';
    }
  }
}