請各位大大幫個忙~

 以下是我的程式碼

#include <iostream>
#include <cmath>

using namespace std;

int main(){
   int a,b,c,D,x,x1,x2;
   while(cin >> a>> b>>c)
   D = b*b-4*a*c;
   x = -b/(2*a);
   x1 =((-b +  sqrt (D))/(2*a));
   x2 = ((-b - sqrt (D) )/(2*a));
  
  if (D<0)
      cout << "No real root "<<endl;
   else if (D==0)
        cout << "Two same roots x=" << x << endl;
        else
  cout << "Two different roots x1=" << x1 << ", x2=" << x2 << endl;
   return 0;

}

*** 第 1 點 (20%)：WA (line:1)
您的答案為: Two different roots x1= 3, x2=2
正確答案為: Two different roots x1=3 , x2=2