#5055: C++ 如何改進


tg20710 (Ina)


#include <cstdlib>
#include <iostream>

using namespace std;

int main(int argc, char *argv[])
{
    int a,b,c;
    cin >> a >> b >> c;
    if (a*a+b*b==c*c||a*a+c*c==b*b||b*b+c*c==a*a){cout << "right triangle" << endl;}
    else if (a*a+b*b>c*c&&a*a+c*c>b*b&&b*b+c*c>a*a){cout << "acute triangle" << endl;}
    else {cout << "obtuse triangle" << endl;}
     return EXIT_SUCCESS;
}

#19401: Re:C++ 如何改進


ryanking0220@gmail.com (金睿霖)


#include
#include

using namespace std;

int main(int argc, char *argv[])
{
    int a,b,c;
    cin >> a >> b >> c;
    if (a*a+b*b==c*c||a*a+c*c==b*b||b*b+c*c==a*a){cout << "right triangle" << endl;}
    else if (a*a+b*b>c*c&&a*a+c*c>b*b&&b*b+c*c>a*a){cout << "acute triangle" << endl;}
    else {cout << "obtuse triangle" << endl;}
     return EXIT_SUCCESS;
}



可以從他移動的步數去思考

這是我的程式碼

#include <iostream>

using namespace std;

int main()

{

int A , B , a , b;

while(cin>>A>>B>>a>>b)

{

if(A==0&&b==0&&B==0&&a==0)

break;

int mx= max(A ,a)-min(A ,a);

int my = max(B ,b)-min(B ,b);

if(mx==0&&my==0)

cout<<0<<endl;

else if(mx==0&&my!=0||mx!=0&&my==0||mx==my!=0)

cout<<1<<endl;

else 

cout<<2<<endl;

}

return 0;

}