#54571: 解決python測資問題的解法
s313048@gm.hccvs.hc.edu.tw
(資二2-11曾奕升)
如何處理測資問題
math = input()
calculat = math.split()
calculat = [int(x) for x in calculat if x.isdigit()]<---加上過濾，if x.isdigit
judge = True
a_and = True
a_or = True
a_xor = True
if calculat[0] != 0 and calculat[1] != 0:
if calculat[2] == 0:
a_xor = False
if calculat[2] == 1:
a_and = False
a_or = False
if calculat[0] == 0 and calculat[1] != 0:
if calculat[2] == 0:
a_and = False
else:
a_xor = False
a_or = False
if calculat[0] == 0 and calculat[1] == 0:
if calculat[2] == 0:
a_and = False
a_xor = False
a_or = False
else:
judge = False
if calculat[0] != 0 and calculat[1] == 0:
if calculat[2] == 0:
a_and = False
else:
a_xor = False
a_or = False
if not judge:
print("IMPOSSIBLE")
if not a_and:
print("AND")
if not a_or:
print("OR")
if not a_xor:
print("XOR")
加上過濾就解決了