#5481: __WA


dk394u4bp6 (???)


我的答案是3010 正解30 10

我的程式碼是#include <iostream>

using namespace std;

int main(){

int n, s, d;

cin>>n;

while(n--){

cin>>s>>d;

if(d>s||((s+d)%2)!=0)

cout<<"impossible\n";

else

cout<<(s+d)/2<<(s-d)/2<<endl;

}

#5482: Re:WA


leopan0922 (zz)


我的答案是3010 正解30 10

我的程式碼是#include

using namespace std;

int main(){

int n, s, d;

cin>>n;

while(n--){

cin>>s>>d;

if(d>s||((s+d)%2)!=0)

cout<<"impossible\n";

else

cout<<(s+d)/2<<(s-d)/2<

}

輸出少一個空白cout<<(s+d)/2<<' '<<(s-d)/2<<endl;