#55387: Solution in Python


evechou270@gmail.com (Chris)


import sys
def lcs(first, second):
    before=list(first)
    after=list(second)
    dp=[]
    for _ in range(len(before)+1):
        dp.append([0] *(len(after)+1))
    for i in range(1, len(before)+1):
        for j in range(1, len(after)+1):
            if before[i-1]==after[j-1]:
                dp[i][j]=dp[i-1][j-1]+1
            else:
                dp[i][j]=max(dp[i-1][j], dp[i][j-1])
    return dp[len(before)][len(after)]
    
while True:
    try:
        one=input()
        two=input()
        print(lcs(one, two))
    except EOFError:
        break