您的答案為: no 正確答案為: yes

#include<iostream> using namespace std; int main(){           int a,x,y;     char sentence[1000];          while(cin>>sentence){         a=0;                                       while(true){                                    if(sentence[a]=='\0'){                                          x=0;                                        y=a-1;                                       break;                                    }                                    else                                       a++;                        }             for(int j=x;j<y;j++){              if(sentence[x]!=sentence[y]){                  cout<<"no\n"<<endl;                  break;              }              else{                  cout<<"yes\n"<<endl;                  break;              }                   }     }      return 0; } 

哪裡錯了