本題可以先做1~4的數字。 EX: 1234

其他大於4位數的數字就可以拆開依序帶入function即可

EX: 1234,5678,9001

可分成3部分依序去解

1234

5678

9001

最後合併就可以了

[簡答]:

#include <stdio.h>

#include <iostream>

#include <string.h>

using namespace std;

char* digit[6] = {"","拾","佰","仟","萬","億"};

char* text[10]  = {"零","壹","貳","參","肆","伍","陸","柒","捌","玖"};

bool BaseMath(char*num)

{

bool lastNumIsZero = false;

int numLen = strlen(num);

if(numLen > 4){cout << "ERROR" << endl; return false;}

if(numLen == 4){

if(num[0] == '0' && num[1] == '0'&& num[2] == '0' && num[3] == '0')

return false;

}

for(int i=0; i<numLen ; ++i){

if(num[i] == '0'){

bool remainIsZero = true;

for(int j=i+1 ; j < numLen ; ++j){

if(num[j] != '0') remainIsZero = false;

}

if(!lastNumIsZero && !remainIsZero) cout << text[0];

lastNumIsZero = true;

}

if(num[i] != '0'){ 

lastNumIsZero = false;

int tindex = num[i] -'0';

int dindex = numLen-i-1;

cout << text[tindex]

   << digit[dindex];

}

}

return true;

}

void SplitMath(char* num)

{

int numLen = strlen(num);

if(numLen < 5){

BaseMath(num);

cout << endl;

}else if(numLen < 9){

char M_Math[5];

char L_Math[5];

int mindex = numLen - 4;

int i=0;

for(i ; i<mindex ; ++i ){

M_Math[i] = num[i];

}M_Math[i] = '\0';

strcpy(L_Math,&num[mindex]);

if(BaseMath(M_Math))

cout << digit[4];

BaseMath(L_Math);

cout << endl;

}else if(numLen < 13){

char B_Math[5];

char M_Math[5];

char L_Math[5];

int bindex = numLen - 8;

int mindex = numLen - 4;

int i=0;

for(i ; i<bindex ; ++i ){

B_Math[i] = num[i];

}B_Math[i] = '\0';

int j=bindex;

int k = 0;

for(j,k ; j<mindex ; ++j, ++k ){

M_Math[k] = num[j];

}M_Math[k] = '\0';

strcpy(L_Math,&num[mindex]);

if(BaseMath(B_Math))

cout << digit[5];

if(BaseMath(M_Math))

cout << digit[4];

BaseMath(L_Math);

cout << endl;

}

}

int main()

{

char str[101];

while(cin >> str){

SplitMath(str);

}

return 0;

}