#include<stdlib.h>
#include<stdio.h>
#include<math.h>
int main(void)
{ float a,b,c;
  float x1,x2;
 while(scanf("%d %d %d",&a,&b,&c))
{
  x1=(-b+sqrt(b*b-4*a*c))/2*a;
  x2=(-b-sqrt(b*b-4*a*c))/2*a;
  if((b*b-4*a*c)>0)
    printf("Two different roots x1=%.0f , x2=%.0f \n",x1,x2); 
  if((b*b-4*a*c)==0)  
    printf("Two same roots x=%.0f \n",x1);
  if((b*b-4*a*c)<0)  
    printf("No real root \n"); 
 }
  return 0; 
} 

假設ax^2+bx+c=0

求出X值?

出來都是0 如何解決