a005. Eva 的回家作業 -- POJ | From: [120.127.47.211] | 發表日期 : 2013-06-16 12:19

#include <iostream>

using namespace std;

int main()

{

int ans,a[20],b[20],c[20],d[20],k,r,i;

cin>>ans;

for(i=0;i<ans;i++)

{

cin>>a[i]>>b[i]>>c[i]>>d[i];

}

cout<<endl;

for(int i=0;i<ans;i++)

{

if(b[i]-a[i]==c[i]-b[i])

{

k=b[i]-a[i];

cout<<a[i]<<" "<<b[i]<<" "<<c[i]<<" "<<d[i]<<" "<<d[i]+k;

}

if(b[i]/a[i]==c[i]/b[i])

{

r=b[i]/a[i];

cout<<a[i]<<" "<<b[i]<<" "<<c[i]<<" "<<d[i]<<" "<<d[i]*r;

}

   cout<<endl;

}

}