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#include<iostream>        
using namespace std;        
int main()     
{     
         
    int n,y;     
    while(cin>>y){     
        if(y%4==0 && y%100!=0 || y%400==0)  
   cout<<"This is leap year."<<endl;
        else if(y%15==0)
            cout<<"This is huluculu festival year."<<endl;
  else
   cout<<"This is an ordinary year."<<endl;
 }     
system("pause");        
return 0;        
} 

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line4就掛了...

我輸出為This is an ordinary year.

正確答案為This is huluculu festival year.

 

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一個年份有可能同時符合幾個特性，例如，2040 年既是閏年，也是 hulukulu 年，那麼這兩種特性你都要印出來，而且要依題目所指定的順序印出來。