#13705: 可使用length()及.at()解題
dartgoblin
(EMU300)
#include<iostream>
#include<cstring>
using namespace std;
int main(){
string s1,s2;
while(cin>>s1>>s2){
int a=s1.at(0),b=s2.at(0);
int k;
if(b>=a)
k=b-a;
else
k=26-(a-b);
cout<<k<<endl;
}
}
#14895: Re:可使用length()及.at()解題
#include
#include
using namespace std;
int main(){
string s1,s2;
while(cin>>s1>>s2){
int a=s1.at(0),b=s2.at(0);
int k;
if(b>=a)
k=b-a;
else
k=26-(a-b);
cout<<k<<endl;
}
}
#include <bits/stdc++.h>
using namespace std;
/* run this program using the console pauser or add your own getch, system("pause") or input loop */
int main(int argc, char** argv) {
string a,b;
while(cin>>a>>b){
if(b[0]>=a[0])cout<<(b[0]-a[0])<<endl;
else cout<<(b[0]-a[0]+26)<<endl;
}
return 0;
}
#17429: Re:可使用length()及.at()解題
ufve0704
(爬 我爬 我爬爬爬 有排行榜這種東西就是要爬 爬過我上面的那...)
#include
#include
using namespace std;
int main(){
string s1,s2;
while(cin>>s1>>s2){
int a=s1.at(0),b=s2.at(0);
int k;
if(b>=a)
k=b-a;
else
k=26-(a-b);
cout<<k<<endl;
}
}
#include <bits/stdc++.h>
using namespace std;
/* run this program using the console pauser or add your own getch, system("pause") or input loop */
int main(int argc, char** argv) {
string a,b;
while(cin>>a>>b){
if(b[0]>=a[0])cout<<(b[0]-a[0])<<endl;
else cout<<(b[0]-a[0]+26)<<endl;
}
return 0;
}
#include <bits/stdc++.h>
using namespace std;
int main(){
string a,b;
while(cin>>a>>b)
cout<<(b[0]-a[0]+26)%26<<endl;
}
這樣更短喔!