#25653: 很簡單的 AC


s910251@student.cysh.cy.edu.tw (吳亮佑)


#include <iostream>
using namespace std;
int main(){
  int n,j,sum;
  while (cin>>n){
    sum=0;
    j=1 ;
    for(j=1;j<n;j++){                    
      if ((n%j) == 0) {
        sum= sum+ j    ;
      }
        ;   
    }       
    if ( sum>n ){
      cout << "盈數" << endl;    
    } else if (  sum<n  ) {
      cout << "虧數" << endl;       
    } else {
      cout << "完全數" << endl;     
    }  
  }
}

加油