#54432: C++解法


william000000000 (unknown)


#include <iostream>

using namespace std;

int main()
{
    int t, year;
    cin >> t;

    for (int i = 1; i <= t; i++) {
        cin >> year;
        if (year % 4 == 0 && year % 100 != 0 || year % 400 == 0) {
            cout << "Case " << i << ": a leap year" << endl;
        }
        else {
            cout << "Case " << i << ": a normal year" << endl;
        }
    }
    return 0;
}