#54925: C語言解題
homjkimo@gmail.com
(ho david)
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char* thousands[] = { "", "M", "MM", "MMM" };
char* hundreds[] = { "", "C", "CC", "CCC", "CD", "D", "DC", "DCC", "DCCC", "CM" };
char* tens[] = { "", "X", "XX", "XXX", "XL", "L", "LX", "LXX", "LXXX", "XC" };
char* ones[] = { "", "I", "II", "III", "IV", "V", "VI", "VII", "VIII", "IX" };
int romtran(char);
int parseR(char*);
char* parseStoR(int num);
int main(int argc, char* argv[]) {
char buffer[50] = "\0";
char num0[20] = "\0";
char num1[20] = "\0";
while (1) {
if (fgets(buffer, sizeof(buffer), stdin) == NULL) {
return 0;
}
if (strcmp(buffer, "#\n") == 0) {
return 0;
}
// 使用sscanf_s
if (sscanf_s(buffer, "%19s %19s", num0, (unsigned)_countof(num0), num1, (unsigned)_countof(num1)) != 2) {
continue;
}
int romnum1, romnum2;
romnum1 = parseR(num0);
romnum2 = parseR(num1);
char* result = parseStoR(romnum1 - romnum2);
if (result != NULL) {
printf("%s\n", result);
// 釋放記憶體（除非是靜態字串）
if (strcmp(result, "ZERO") != 0 && strcmp(result, "negative") != 0) {
free(result);
}
}
}
return 0;
}
int romtran(char ch) {
switch (ch) {
case 'I':
case 'i':
return 1;
case 'V':
case 'v':
return 5;
case 'X':
case 'x':
return 10;
case 'L':
case 'l':
return 50;
case 'C':
case 'c':
return 100;
case 'D':
case 'd':
return 500;
case 'M':
case 'm':
return 1000;
default:
return 0;
}
}
int parseR(char* R) {
int total = 0;
int prev = 0;
//*****右到左解析羅馬數字*****
for (int i = strlen(R) - 1; i >= 0; i--) {
int curr = romtran(R[i]);
int sign = (curr < prev) ? -1 : 1;
total += sign * curr;
prev = curr;
}
return total;
}
char* parseStoR(int num) {
if (num == 0)
return "ZERO";
if (num < 0)
return "negative";
if (num > 3999)
return "overflow"; // 或你想要的字串
char* result = (char*)malloc(32);
if (!result) return NULL;
result[0] = '\0';
strcat_s(result, 32, thousands[num / 1000]);
strcat_s(result, 32, hundreds[(num % 1000) / 100]);
strcat_s(result, 32, tens[(num % 100) / 10]);
strcat_s(result, 32, ones[num % 10]);
return result;
}
#54926: Re: C語言解題
homjkimo@gmail.com
(ho david)
#include <stdio.h>#include <stdlib.h>#include <string.h>char* thousands[] = { "", "M", "MM", "MMM" };char* hundreds[] = { "", "C", "CC", "CCC", "CD", "D", "DC", "DCC", "DCCC", "CM" };char* tens[] = { "", "X", "XX", "XXX", "XL", "L", "LX", "LXX", "LXXX", "XC" };char* ones[] = { "", "I", "II", "III", "IV", "V", "VI", "VII", "VIII", "IX" };int romtran(char);int parseR(char*);char* parseStoR(int num);
int main(int argc, char* argv[]) {char buffer[50] = "\0";char num0[20] = "\0";char num1[20] = "\0";
while (1) {if (fgets(buffer, sizeof(buffer), stdin) == NULL) {return 0;}if (strcmp(buffer, "#\n") == 0) {return 0;}
// 使用sscanf解析輸入，確保不會溢出if (sscanf(buffer, "%19s %19s", num0, num1) != 2) {continue;}
int romnum1, romnum2;romnum1 = parseR(num0);romnum2 = parseR(num1);char* result = parseStoR(abs(romnum1 - romnum2));if (result != NULL) {printf("%s\n", result);// 釋放記憶體（除非是靜態字串）if (strcmp(result, "ZERO") != 0 && strcmp(result, "negative") != 0) {free(result);}}}return 0;}
int romtran(char ch) {switch (ch) {case 'I':case 'i':return 1;case 'V':case 'v':return 5;case 'X':case 'x':return 10;case 'L':case 'l':return 50;case 'C':case 'c':return 100;case 'D':case 'd':return 500;case 'M':case 'm':return 1000;default:return 0;}}
int parseR(char* R) {int total = 0;int prev = 0;//*****右到左解析羅馬數字*****for (int i = strlen(R) - 1; i >= 0; i--) {int curr = romtran(R[i]);int sign = (curr < prev) ? -1 : 1;total += sign * curr;prev = curr;}return total;}
char* parseStoR(int num) {if (num == 0)return "ZERO";
if (num < 0)return "negative";
if (num > 3999)return "overflow"; // 或你想要的字串
char* result = (char*)malloc(32);if (!result) return NULL;
result[0] = '\0';
strcat(result, thousands[num / 1000]);strcat(result, hundreds[(num % 1000) / 100]);strcat(result, tens[(num % 100) / 10]);strcat(result, ones[num % 10]);
return result;}